Yanina Wickmayer (WTA 116) has without a lot of problems for the quarter-finals of the Challenger tournament in American Indian Wells (hard/ $ 150,000).
Our 28-year-old compatriot beat in the second round of the American Sofia Kenin (WTA 104) in twice 6-3. The match lasted one hour and ten minutes. In the quarter-finals will take Wickmayer against the winner of the duel between the Dutch Richel Hogenkamp (WTA 107) and the Ukrainian Kateryna Bondarenko (WTA 84).
Wickmayer is on the tournament is also still active in the doubles. On the side of thuisspeelster Taylor Townsend will find them in the first round, the Polish Magda Linette and the Swiss Viktorija Golubic.